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DYN:010117Cable x+2y=C with vx=3 and ax=-2 forces vy=-3/2 m/s and ay=1 m/s2

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Dynamics Constraint First DerivativeDynamics Constraint Second Derivative

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Particle kinematics in multiple coordinatesEngineering Dynamics · Mixed review

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DYN:010118Collar absolute velocity is (5,0); five-term acceleration is (-1,17.5)

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Dynamics Relative Velocity Rotating FrameDynamics Five Term Acceleration

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Particle kinematics in multiple coordinatesEngineering Dynamics · Mixed review

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DYN:010132Helix r=(3cos2t,3sin2t,4t) has speed 2sqrt13; at t=0 the Frenet data are T=(0,3/sqrt13,2/sqrt13), N=(-1,0,0), B=(0,-2/sqrt13,3/sqrt13), kappa=3/13, tau=2/13, at=0, an=12

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Dynamics Helix Speed From ParametrizationDynamics Frenet Trihedron Curvature Torsion

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Particle kinematics in multiple coordinatesEngineering Dynamics · Mixed review

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DYN:010133Relative path (6-2t,-2+t) is closest at t=14/5 with offset (2/5,4/5), distance 2/sqrt5, and vanishing dot product

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Dynamics Relative Linear MotionDynamics Closest Approach Orthogonality

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Particle kinematics in multiple coordinatesEngineering Dynamics · Mixed review

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DYN:010134Parabola r=(10t,10t-5t^2) reenters y=x/2 at (10,5); plane travel is 5sqrt5, v=(10,0) splits as 4sqrt5 and -2sqrt5 on (2,1)/sqrt5 and (-1,2)/sqrt5

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Dynamics Parabola Plane IntersectionDynamics Plane Tangent Normal Resolution

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Particle kinematics in multiple coordinatesEngineering Dynamics · Mixed review

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DYN:010219B descends; a=g(2-sqrt3)/14 and T=3g(12+sqrt3)/14 after a motion audit

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Dynamics Kinetic Friction InclineDynamics Motion Assumption Audit

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Particle force-acceleration methodsEngineering Dynamics · Mixed review

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DYN:010220At t=1 the polar force is -10 e_r+8 e_theta N; the slot supplies the 8 N

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Dynamics Polar Acceleration ComponentsDynamics Slot Reaction VS Actuator

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Particle force-acceleration methodsEngineering Dynamics · Mixed review

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DYN:010235Conical pendulum m=2, L=2, g=10, theta=60 deg has radius sqrt3, T=40 N, speed sqrt30, rate sqrt10, period 2pi/sqrt10

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Dynamics Conical Vertical Horizontal SplitDynamics Cone Radius Rate Period

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Particle force-acceleration methodsEngineering Dynamics · Mixed review

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DYN:010236Hoop R=2, Omega=sqrt10, g=10 holds a bead at cosθ=1/2 from downward; radius sqrt3, centripetal 10sqrt3, reaction 20 from 10sqrt3 inward and 10 up

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Dynamics Spinning Hoop Effective PotentialDynamics Hoop Reaction From Circular Demand

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Particle force-acceleration methodsEngineering Dynamics · Mixed review

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DYN:010237Frictionless bank tanθ=3/4 yields N=25 N and v=5sqrt6 m/s

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Dynamics Banked Normal ResolutionDynamics Frictionless Design Speed

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Particle force-acceleration methodsEngineering Dynamics · Mixed review

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DYN:010321Elevator shaft output is 40.68 kW; supplied input at eta=0.8 is 50.85 kW

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Dynamics Cable Tension From AccelerationDynamics Mechanical VS Input Power

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Work-energy and impulse-momentumEngineering Dynamics · Mixed review

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DYN:010322The impulse (12,8) N s sends vf to (6,5/3) m/s and does 152/3 J of work

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Dynamics Vector Impulse IntegralDynamics Work Energy Variable Force

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Work-energy and impulse-momentumEngineering Dynamics · Mixed review

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DYN:010323The force 6x^2 does 16 J of work; the final power is 24sqrt17 W

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Dynamics Position Force Work IntegralDynamics Instantaneous Power Potential

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Work-energy and impulse-momentumEngineering Dynamics · Mixed review

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DYN:010338Central pull keeps H=12, raises vθ from 3 to 6, and does 27 J

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Dynamics Central Angular MomentumDynamics String Work From Kinetic

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Work-energy and impulse-momentumEngineering Dynamics · Mixed review

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DYN:010339Inner-loop contact needs hmin=5R/2; at h=3R the top normal is mg

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Dynamics Loop Leave Contact ThresholdDynamics Energy TO Top Normal

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Work-energy and impulse-momentumEngineering Dynamics · Mixed review

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DYN:010424Rigid kinematics give vB=(-2,2+3sqrt3) and aB=(1-9sqrt3,-6-2sqrt3)

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Dynamics Rigid Relative VelocityDynamics Rigid Relative Acceleration

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Planar rigid-body kinematicsEngineering Dynamics · Mixed review

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DYN:010425External gears send the top rack right at 0.4 m/s and 0.16 m/s^2

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Dynamics External Gear RatioDynamics Pinion Rack Tangential Match

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Planar rigid-body kinematicsEngineering Dynamics · Mixed review

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DYN:010440Slider-crank at θ=π/2 has x=sqrt3, vx=-2, and ax=4/sqrt3

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Dynamics Holonomic Slider DerivativesDynamics Theta TO Time Acceleration

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Planar rigid-body kinematicsEngineering Dynamics · Mixed review

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DYN:010441Guided coupler gives vC=(8,0) and aC=(-154/3,0) by vector kinematics

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Dynamics Guided Link Vector VelocityDynamics Guided Link Vector Acceleration

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Planar rigid-body kinematicsEngineering Dynamics · Mixed review

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DYN:010442Slot constraint at (3,4) forces ydot=-3/2 and yddot=-13/16; floor-angle omega=-1/2 and alpha=1/16

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Dynamics Slot Constraint Second DerivativeDynamics Floor Angle Rigid Rod

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Planar rigid-body kinematicsEngineering Dynamics · Mixed review

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DYN:010526A released pinned bar has alpha=-15/2 rad/s^2 and pin reaction (0,15) N

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Dynamics End Pinned Bar InertiaDynamics Release Pin Reaction

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Planar rigid-body kineticsEngineering Dynamics · Mixed review

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DYN:010527Angular impulse 8 N m s takes the flywheel from 4 to 52/5 rad/s; the work is 288/5 J

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Dynamics Angular Impulse MomentumDynamics Rotational Work Energy

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Planar rigid-body kineticsEngineering Dynamics · Mixed review

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DYN:010528The free disk reaches v=4 m/s and omega=12 rad/s; translational work 32 J and rotational work 36 J total 68 J

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Dynamics Unconstrained Plane KineticsDynamics Force Couple Work Split

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Planar rigid-body kineticsEngineering Dynamics · Mixed review

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DYN:010543A 12 N offset on the 6 kg square gives aG=2 i, M=-12 k, alpha=-3 k, and aP=5 i

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Dynamics Mass Center TranslationDynamics Offset Force Spin

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Planar rigid-body kineticsEngineering Dynamics · Mixed review

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DYN:010544Transverse impulse 6 N s at the rod end yields vG=2 j, omega=6 k, end speeds 8 and -4, KE=24 J

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Dynamics Linear Angular ImpulseDynamics Rigid End Velocity After Impulse

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Planar rigid-body kineticsEngineering Dynamics · Mixed review

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DYN:010629Underdamped free decay has omega_d=4 and log decrement 3pi/2; same-phase peaks ratio e^{3pi/2}

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Dynamics Underdamped Free ConstantsDynamics Log Decrement

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Single-degree vibration and responseEngineering Dynamics · Mixed review

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DYN:010630Coulomb half-cycle loss is 0.04 m; the mass sticks after 7 half-cycles at 7pi/10 s

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Dynamics Coulomb Half Cycle LossDynamics Coulomb Stick Threshold

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Single-degree vibration and responseEngineering Dynamics · Mixed review

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DYN:010631Parallel torsional springs give omega_n=2sqrt2; amplitude sqrt6/20 rad and energy 3/25 J

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Dynamics Parallel Torsional StiffnessDynamics Sdof Torsional IC

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Single-degree vibration and responseEngineering Dynamics · Mixed review

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DYN:010645Gravity step from slack is x=(2/5)(1-cos 5t); vmax=2 at pi/10 and xmax=4/5 with spring 40 N

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Dynamics Shift TO Static EquilibriumDynamics Step Oscillator Extrema

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Single-degree vibration and responseEngineering Dynamics · Mixed review

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DYN:010646Critical release x=(1/10+t/5)e^{-2t} has no overshoot; peak speed 1/(5e) at t=1/2

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Dynamics Critical Damping RecognitionDynamics Critically Damped Peak Speed

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Single-degree vibration and responseEngineering Dynamics · Mixed review

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903011A particle moving along a straight line has velocity v = (12 − 3 t) m/s for 0 ≤ t ≤ 8 s, where t is in seconds.

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903012A particle traveling along a straight line has acceleration a = 3.0 m/s² for 0 ≤ t < 4 s and a = −1.5 m/s² for t ≥…

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903013The v–t graph of a particle moving along a straight line consists of a straight line from (t, v) = (0 s, 0) to (4 s…

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903014The a–t graph of a particle moving along a straight line consists of a = 2.5 m/s² from t = 0 to t = 3 s, a = 0 from…

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903015The s–t graph of a particle moving along a straight line is a straight line from (t, s) = (0 s, 0) to (5 s, 15 m),…

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903016The v–s graph of a particle moving along a straight line is a straight line from (s, v) = (0, 4 m/s) to (12 m, 10 m…

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903017The a–t graph of a particle moving along a straight line consists of a straight line from (t, a) = (0, 0) to (6 s,…

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903018Car A travels in a straight lane at a constant speed of 22 m/s.

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903019Two particles approach each other along the same straight line.

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903020At t = 0, particles P, Q, and R are on the same straight line at s_P = 0, s_Q = 18 m, and s_R = 45 m.

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Problem library

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DYN:010117Cable x+2y=C with vx=3 and ax=-2 forces vy=-3/2 m/s and ay=1 m/s2

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Dynamics Constraint First DerivativeDynamics Constraint Second Derivative

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Particle kinematics in multiple coordinatesEngineering Dynamics · Mixed review

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DYN:010118Collar absolute velocity is (5,0); five-term acceleration is (-1,17.5)

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Dynamics Relative Velocity Rotating FrameDynamics Five Term Acceleration

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Particle kinematics in multiple coordinatesEngineering Dynamics · Mixed review

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DYN:010132Helix r=(3cos2t,3sin2t,4t) has speed 2sqrt13; at t=0 the Frenet data are T=(0,3/sqrt13,2/sqrt13), N=(-1,0,0), B=(0,-2/sqrt13,3/sqrt13), kappa=3/13, tau=2/13, at=0, an=12

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Dynamics Helix Speed From ParametrizationDynamics Frenet Trihedron Curvature Torsion

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Particle kinematics in multiple coordinatesEngineering Dynamics · Mixed review

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DYN:010133Relative path (6-2t,-2+t) is closest at t=14/5 with offset (2/5,4/5), distance 2/sqrt5, and vanishing dot product

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Dynamics Relative Linear MotionDynamics Closest Approach Orthogonality

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Particle kinematics in multiple coordinatesEngineering Dynamics · Mixed review

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DYN:010134Parabola r=(10t,10t-5t^2) reenters y=x/2 at (10,5); plane travel is 5sqrt5, v=(10,0) splits as 4sqrt5 and -2sqrt5 on (2,1)/sqrt5 and (-1,2)/sqrt5

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Dynamics Parabola Plane IntersectionDynamics Plane Tangent Normal Resolution

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Particle kinematics in multiple coordinatesEngineering Dynamics · Mixed review

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DYN:010219B descends; a=g(2-sqrt3)/14 and T=3g(12+sqrt3)/14 after a motion audit

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Dynamics Kinetic Friction InclineDynamics Motion Assumption Audit

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Particle force-acceleration methodsEngineering Dynamics · Mixed review

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DYN:010220At t=1 the polar force is -10 e_r+8 e_theta N; the slot supplies the 8 N

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Dynamics Polar Acceleration ComponentsDynamics Slot Reaction VS Actuator

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Particle force-acceleration methodsEngineering Dynamics · Mixed review

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DYN:010235Conical pendulum m=2, L=2, g=10, theta=60 deg has radius sqrt3, T=40 N, speed sqrt30, rate sqrt10, period 2pi/sqrt10

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Dynamics Conical Vertical Horizontal SplitDynamics Cone Radius Rate Period

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Particle force-acceleration methodsEngineering Dynamics · Mixed review

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DYN:010236Hoop R=2, Omega=sqrt10, g=10 holds a bead at cosθ=1/2 from downward; radius sqrt3, centripetal 10sqrt3, reaction 20 from 10sqrt3 inward and 10 up

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Dynamics Spinning Hoop Effective PotentialDynamics Hoop Reaction From Circular Demand

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Particle force-acceleration methodsEngineering Dynamics · Mixed review

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DYN:010237Frictionless bank tanθ=3/4 yields N=25 N and v=5sqrt6 m/s

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Dynamics Banked Normal ResolutionDynamics Frictionless Design Speed

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Particle force-acceleration methodsEngineering Dynamics · Mixed review

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DYN:010321Elevator shaft output is 40.68 kW; supplied input at eta=0.8 is 50.85 kW

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Dynamics Cable Tension From AccelerationDynamics Mechanical VS Input Power

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Work-energy and impulse-momentumEngineering Dynamics · Mixed review

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DYN:010322The impulse (12,8) N s sends vf to (6,5/3) m/s and does 152/3 J of work

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Dynamics Vector Impulse IntegralDynamics Work Energy Variable Force

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Work-energy and impulse-momentumEngineering Dynamics · Mixed review

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DYN:010323The force 6x^2 does 16 J of work; the final power is 24sqrt17 W

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Dynamics Position Force Work IntegralDynamics Instantaneous Power Potential

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Work-energy and impulse-momentumEngineering Dynamics · Mixed review

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DYN:010338Central pull keeps H=12, raises vθ from 3 to 6, and does 27 J

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Dynamics Central Angular MomentumDynamics String Work From Kinetic

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Work-energy and impulse-momentumEngineering Dynamics · Mixed review

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DYN:010339Inner-loop contact needs hmin=5R/2; at h=3R the top normal is mg

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Dynamics Loop Leave Contact ThresholdDynamics Energy TO Top Normal

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Work-energy and impulse-momentumEngineering Dynamics · Mixed review

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DYN:010424Rigid kinematics give vB=(-2,2+3sqrt3) and aB=(1-9sqrt3,-6-2sqrt3)

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Dynamics Rigid Relative VelocityDynamics Rigid Relative Acceleration

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Planar rigid-body kinematicsEngineering Dynamics · Mixed review

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DYN:010425External gears send the top rack right at 0.4 m/s and 0.16 m/s^2

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Dynamics External Gear RatioDynamics Pinion Rack Tangential Match

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Planar rigid-body kinematicsEngineering Dynamics · Mixed review

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DYN:010440Slider-crank at θ=π/2 has x=sqrt3, vx=-2, and ax=4/sqrt3

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Dynamics Holonomic Slider DerivativesDynamics Theta TO Time Acceleration

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Planar rigid-body kinematicsEngineering Dynamics · Mixed review

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DYN:010441Guided coupler gives vC=(8,0) and aC=(-154/3,0) by vector kinematics

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Dynamics Guided Link Vector VelocityDynamics Guided Link Vector Acceleration

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Planar rigid-body kinematicsEngineering Dynamics · Mixed review

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DYN:010442Slot constraint at (3,4) forces ydot=-3/2 and yddot=-13/16; floor-angle omega=-1/2 and alpha=1/16

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Dynamics Slot Constraint Second DerivativeDynamics Floor Angle Rigid Rod

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Planar rigid-body kinematicsEngineering Dynamics · Mixed review

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DYN:010526A released pinned bar has alpha=-15/2 rad/s^2 and pin reaction (0,15) N

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Dynamics End Pinned Bar InertiaDynamics Release Pin Reaction

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Planar rigid-body kineticsEngineering Dynamics · Mixed review

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DYN:010527Angular impulse 8 N m s takes the flywheel from 4 to 52/5 rad/s; the work is 288/5 J

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Dynamics Angular Impulse MomentumDynamics Rotational Work Energy

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Planar rigid-body kineticsEngineering Dynamics · Mixed review

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DYN:010528The free disk reaches v=4 m/s and omega=12 rad/s; translational work 32 J and rotational work 36 J total 68 J

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Dynamics Unconstrained Plane KineticsDynamics Force Couple Work Split

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Planar rigid-body kineticsEngineering Dynamics · Mixed review

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DYN:010543A 12 N offset on the 6 kg square gives aG=2 i, M=-12 k, alpha=-3 k, and aP=5 i

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Dynamics Mass Center TranslationDynamics Offset Force Spin

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Planar rigid-body kineticsEngineering Dynamics · Mixed review

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DYN:010544Transverse impulse 6 N s at the rod end yields vG=2 j, omega=6 k, end speeds 8 and -4, KE=24 J

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Dynamics Linear Angular ImpulseDynamics Rigid End Velocity After Impulse

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Planar rigid-body kineticsEngineering Dynamics · Mixed review

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DYN:010629Underdamped free decay has omega_d=4 and log decrement 3pi/2; same-phase peaks ratio e^{3pi/2}

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Dynamics Underdamped Free ConstantsDynamics Log Decrement

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Single-degree vibration and responseEngineering Dynamics · Mixed review

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DYN:010630Coulomb half-cycle loss is 0.04 m; the mass sticks after 7 half-cycles at 7pi/10 s

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Dynamics Coulomb Half Cycle LossDynamics Coulomb Stick Threshold

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Single-degree vibration and responseEngineering Dynamics · Mixed review

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DYN:010631Parallel torsional springs give omega_n=2sqrt2; amplitude sqrt6/20 rad and energy 3/25 J

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Dynamics Parallel Torsional StiffnessDynamics Sdof Torsional IC

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Single-degree vibration and responseEngineering Dynamics · Mixed review

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DYN:010645Gravity step from slack is x=(2/5)(1-cos 5t); vmax=2 at pi/10 and xmax=4/5 with spring 40 N

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Dynamics Shift TO Static EquilibriumDynamics Step Oscillator Extrema

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Single-degree vibration and responseEngineering Dynamics · Mixed review

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DYN:010646Critical release x=(1/10+t/5)e^{-2t} has no overshoot; peak speed 1/(5e) at t=1/2

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Dynamics Critical Damping RecognitionDynamics Critically Damped Peak Speed

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Single-degree vibration and responseEngineering Dynamics · Mixed review

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903011A particle moving along a straight line has velocity v = (12 − 3 t) m/s for 0 ≤ t ≤ 8 s, where t is in seconds.

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903012A particle traveling along a straight line has acceleration a = 3.0 m/s² for 0 ≤ t < 4 s and a = −1.5 m/s² for t ≥…

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903013The v–t graph of a particle moving along a straight line consists of a straight line from (t, v) = (0 s, 0) to (4 s…

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903014The a–t graph of a particle moving along a straight line consists of a = 2.5 m/s² from t = 0 to t = 3 s, a = 0 from…

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903015The s–t graph of a particle moving along a straight line is a straight line from (t, s) = (0 s, 0) to (5 s, 15 m),…

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903016The v–s graph of a particle moving along a straight line is a straight line from (s, v) = (0, 4 m/s) to (12 m, 10 m…

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903017The a–t graph of a particle moving along a straight line consists of a straight line from (t, a) = (0, 0) to (6 s,…

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903018Car A travels in a straight lane at a constant speed of 22 m/s.

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903019Two particles approach each other along the same straight line.

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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DYN:9903020At t = 0, particles P, Q, and R are on the same straight line at s_P = 0, s_Q = 18 m, and s_R = 45 m.

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Particle KinematicsDynamics Problem Solving

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Particle kinematics in multiple coordinatesEngineering Dynamics · Calculation

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Problem results

DYN:9903001A particle starts from rest at s = 0 and moves along a straight line with constant acceleration a = 2.4 m/s².

DYN:9903002The position of a particle traveling along a straight line is s = (0.15 t³ − 1.8 t² + 4.2 t) m, where t is in seconds.

DYN:9903003The velocity of a particle moving along a straight line is v = (6 t − 0.75 t²) m/s, where t is in seconds.

DYN:9903004A particle moving along a straight line has acceleration a = (0.40 t² − 1.6) m/s², where t is in seconds.

DYN:9903005The velocity of a particle traveling along a straight line is v = (0.08 s² + 4) m/s, where s is in meters.

DYN:9903006A particle moving along a straight line has acceleration a = (6 − 0.3 s) m/s², where s is in meters.

DYN:9903007The acceleration of a particle traveling along a straight line is a = (0.25 v + 1.5) m/s², where v is in m/s.

DYN:9903008A particle moving along a straight line has acceleration a = −0.40 v² m/s², where v is in m/s.

DYN:9903009A crate is accelerated from rest along a straight warehouse aisle at 1.8 m/s² for 4 s, after which the acceleration…

DYN:9903010A tram starts from rest, accelerates at 0.90 m/s² for 8 s, travels at constant speed for 20 s, and then decelerates…

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Problem results

DYN:9903001A particle starts from rest at s = 0 and moves along a straight line with constant acceleration a = 2.4 m/s².

DYN:9903002The position of a particle traveling along a straight line is s = (0.15 t³ − 1.8 t² + 4.2 t) m, where t is in seconds.

DYN:9903003The velocity of a particle moving along a straight line is v = (6 t − 0.75 t²) m/s, where t is in seconds.

DYN:9903004A particle moving along a straight line has acceleration a = (0.40 t² − 1.6) m/s², where t is in seconds.

DYN:9903005The velocity of a particle traveling along a straight line is v = (0.08 s² + 4) m/s, where s is in meters.

DYN:9903006A particle moving along a straight line has acceleration a = (6 − 0.3 s) m/s², where s is in meters.

DYN:9903007The acceleration of a particle traveling along a straight line is a = (0.25 v + 1.5) m/s², where v is in m/s.

DYN:9903008A particle moving along a straight line has acceleration a = −0.40 v² m/s², where v is in m/s.

DYN:9903009A crate is accelerated from rest along a straight warehouse aisle at 1.8 m/s² for 4 s, after which the acceleration…

DYN:9903010A tram starts from rest, accelerates at 0.90 m/s² for 8 s, travels at constant speed for 20 s, and then decelerates…