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STAT:010117The moment of F about axis AB is 5sqrt2 kN m from either A or B

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Statics Position Cross MomentStatics Axis Moment Invariance

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Mixed review

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STAT:010118Three concurrent tensions sum to 50(2,1,3) kN; the equilibrant is the opposite vector

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Statics Concurrent Force SumStatics Equilibrant Direction Cosines

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Mixed review

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STAT:010132Two equal-opposite force pairs leave the free couple (-3,0,-8) kN m

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Statics Force Pair Moment AS Free CoupleStatics Resultant Vanishes Origin Independence

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Mixed review

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STAT:010133Forces (4,0) at (0,2), (0,6) at (3,0), (-1,-2) at (1,1) plus +3k give R=(3,4), Mo=12, line 4x-3y=12, closest (48/25,-36/25)

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Statics Planar Resultant And Origin MomentStatics Line OF Action From Moment Match

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Mixed review

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STAT:010134r=(2,-1,1), Fx=3, Mz=11, F·(i+j+k)=12 recover F=(3,4,5); r×F=(-9,-7,11) and r·M=0

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Statics Moment Component From Cross ProductStatics Unnormalized Projection IS Not Direction Cosine

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Mixed review

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STAT:010219Cable tensions 5/3, 20/3, 20/3 kN keep the ring in equilibrium

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Statics Spatial Particle Force BalanceStatics Cable Tension Sign Audit

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Particle and rigid-body equilibriumEngineering Statics · Mixed review

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STAT:010220Vertical ties carry 6 kN and 4 kN; the ball-and-socket reaction is (-4,3,2) kN

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Statics Spatial Rigid Body MomentsStatics Ball Socket Tie Reactions

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Particle and rigid-body equilibriumEngineering Statics · Mixed review

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STAT:010221The two-force link carries 10 kN; the pin reaction (8,2) kN meets the other two lines at (3,3/4)

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Statics Three Force ConcurrencyStatics Two Force Member Direction

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Particle and rigid-body equilibriumEngineering Statics · Mixed review

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STAT:010235Smooth normals n1=(3/5,4/5), n2=(-4/5,3/5) with P i and 70 downward give N1=56-3P/5, N2=42+4P/5; contact iff -105/2<=P<=280/3

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Statics Two Smooth Normal EquilibriumStatics Unilateral Reaction Sign Window

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Particle and rigid-body equilibriumEngineering Statics · Mixed review

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STAT:010236Pin A at x=0 and upward roller B at x=4 with 12 down at x=-1 and P down at x=6: By=(3P-6)/2, Ay=15-P/2; contact iff P>=2

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Statics Pin Roller Overhang Moment BalanceStatics Upward Roller Liftoff Threshold

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Particle and rigid-body equilibriumEngineering Statics · Mixed review

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STAT:010322One section through BC, BE, and DE reads the three cut forces; joints and zero-force are not the method

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Truss Global Support ReactionsMethod OF Sections Three Cut

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Trusses, frames, and machinesEngineering Statics · Mixed review

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STAT:010323The hinge at B transmits force, not a couple; B on AB is not the force on BC

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Internal Hinge DisassemblyThree Pin Frame Equilibrium

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Trusses, frames, and machinesEngineering Statics · Mixed review

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STAT:010324Stage arms 0.60/0.15 and 0.20/0.05 multiply to 16P; the pins are 5P up and 20P down

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Compound Lever Mechanical AdvantagePin Reaction Action Reaction Audit

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Trusses, frames, and machinesEngineering Statics · Mixed review

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STAT:010337Triangle A(0,0),B(4,0),C(0,3) with three vertical rollers has m+r=2j=6 but support-wrench rank 2 and a horizontal mechanism

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Statics Truss Count Necessary Not SufficientStatics Support Wrench Rank Mechanism

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Trusses, frames, and machinesEngineering Statics · Mixed review

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STAT:010338Symmetric cable span 8 sag 2 under w=3 kN/m has H=12, support tension 12sqrt2, midspan y=x^2/8, slope 1, midspan tension 12

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Statics Parabolic Cable Horizontal ThrustStatics Cable Support Slope Tension

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Trusses, frames, and machinesEngineering Statics · Mixed review

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STAT:010425The hole subtracts area; y-bar stays on the midline and x-bar is not the hole center

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Composite Area Signed First MomentCentroid Symmetry And Hole

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Distributed loads, centroids, and resultantsEngineering Statics · Mixed review

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STAT:010426Three orthogonal wires have r_G=(16/25,27/50,8/25); gravity about O is not a wrench pitch

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Composite Wire Mass CenterGravity Moment About Origin

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Distributed loads, centroids, and resultantsEngineering Statics · Mixed review

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STAT:010439Vertical gate width 2 height 3 with top at the free surface and gamma=10 has F=90, center of pressure at depth 2, moment about the top 180

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Statics Hydrostatic Resultant ON RectangleStatics Center OF Pressure Versus Centroid

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Distributed loads, centroids, and resultantsEngineering Statics · Mixed review

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STAT:010440T-section web 2x3 on y=0..3 and flange 6x1 on y=3..4 has areas 6 and 6, ybar=5/2, Ix=17, Iy=20, Ixy=0

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Statics Composite T Section CentroidStatics Parallel Axis Second Moments

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Distributed loads, centroids, and resultantsEngineering Statics · Mixed review

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STAT:010441Linear p=3x+6y on 0<=x<=2, 0<=y<=1 has R=(0,0,-12), M_O=(-7,14,0), vertical resultant through (7/6,7/12)

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Statics Linear Pressure Force ResultantStatics Distributed Moment Line OF Action

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Distributed loads, centroids, and resultantsEngineering Statics · Mixed review

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STAT:010527A pushed block tips before it exhausts static friction

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Tip Versus Slide ThresholdContact Resultant Eccentricity

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Dry friction and impending motionEngineering Statics · Mixed review

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STAT:010528A half-wrap capstan doubles tension at impending slip

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Capstan Differential EquilibriumBelt Friction Torque Capacity

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Dry friction and impending motionEngineering Statics · Mixed review

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STAT:010529A square-thread screw raises easily enough but still self-locks

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Power Screw Friction AngleSelf Locking And Efficiency

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Dry friction and impending motionEngineering Statics · Mixed review

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STAT:010542Horizontal P on a 3-4-5 rough incline with W=100 and mu_s=1/2 admits 200/11<=P<=200; f=+500/11 downslope-impending, f=-100 upslope-impending, and f=0 at 75

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Statics Horizontal Push Incline ResolutionStatics Signed Coulomb Rest Window

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Dry friction and impending motionEngineering Statics · Mixed review

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STAT:010543Drum torque 100 on radius 1/2 needs |F|=200 and N=500 at mu=0.4; lever moments at A=(0.4,0.2) give P=180 versus P=20 according to drum sense

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Statics Drum Pad Friction Normal PairStatics Lever Brake Directional Moment

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Dry friction and impending motionEngineering Statics · Mixed review

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STAT:010630Four supporting cable segments give an ideal four-to-one block tackle

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Cable Length Virtual DisplacementIdeal Block Tackle Advantage

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Potential energy and virtual workEngineering Statics · Mixed review

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STAT:010631A torsional spring turns a rigid-link instability into a pitchfork

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Potential Energy Critical LoadDegenerate Equilibrium Bifurcation

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Potential energy and virtual workEngineering Statics · Mixed review

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STAT:010644External gears r=1/5 and 1/2 convert input 50 through 0.2 dθ1+0.5 dθ2=0 into output 125, tooth force 250, and opposite rotations

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Statics External Gear Constraint RatioStatics Virtual Work Gear Torque

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Potential energy and virtual workEngineering Statics · Mixed review

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STAT:010645Rolling wheel of radius 1/2 with Q=600 left at the center needs P=300 at the top; contact has zero virtual displacement but friction 300 right, N=1000, mu_min=0.30

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Statics Rolling Virtual Displacement RatioStatics Silent Contact Friction Recovery

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Potential energy and virtual workEngineering Statics · Mixed review

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STAT:010646Smooth vertical circle with V=-R(4cosθ+3sinθ) is stationary at sinθ=3/5, cosθ=4/5 with V''=5R>0 and inward reaction 5; the antipode has V''=-5R and is unstable

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Statics Circle Conservative PotentialStatics Second Derivative Stability Reaction

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Potential energy and virtual workEngineering Statics · Mixed review

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902011A 1.2 kN force acts along the line from A(0, 0, 0) to B(3 m, 4 m, 12 m).

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902012Force F = (50i + 80j − 40k) N is applied at corner G of a rectangular box with corners at O(0,0,0), A(0.6 m,0,0), B…

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902013A 250 N force acts in the negative y-direction at point Q(0.8 m, 0, 0.5 m).

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902014Using Varignon’s theorem, determine the moment about point A of the 600 N force applied at B on the L-shaped member.

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902015Two parallel forces of equal magnitude 400 N but opposite sense form a couple in the x–y plane.

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902016Replace the force F = (120i − 90j) N acting at point (0.4 m, 0.2 m) by an equivalent force–couple system at the ori…

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902017A 3 kN vertical downward force acts at the free end of a horizontal cantilever of length 2.4 m.

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902018The force system on a rigid body consists of F1 = 200i N at (0, 0.5 m), F2 = −150j N at (0.8 m, 0), and a couple of…

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902019Three forces act on a particle: 500 N directed 30° above the positive x-axis, 350 N directed 120° from the positive…

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902020A particle is in equilibrium under four concurrent coplanar forces.

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Problem library

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Topic choices for Engineering Statics are shortened. Search still covers every problem.

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STAT:010117The moment of F about axis AB is 5sqrt2 kN m from either A or B

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Statics Position Cross MomentStatics Axis Moment Invariance

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Mixed review

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STAT:010118Three concurrent tensions sum to 50(2,1,3) kN; the equilibrant is the opposite vector

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Statics Concurrent Force SumStatics Equilibrant Direction Cosines

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Mixed review

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STAT:010132Two equal-opposite force pairs leave the free couple (-3,0,-8) kN m

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Statics Force Pair Moment AS Free CoupleStatics Resultant Vanishes Origin Independence

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Mixed review

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STAT:010133Forces (4,0) at (0,2), (0,6) at (3,0), (-1,-2) at (1,1) plus +3k give R=(3,4), Mo=12, line 4x-3y=12, closest (48/25,-36/25)

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Statics Planar Resultant And Origin MomentStatics Line OF Action From Moment Match

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Mixed review

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STAT:010134r=(2,-1,1), Fx=3, Mz=11, F·(i+j+k)=12 recover F=(3,4,5); r×F=(-9,-7,11) and r·M=0

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Statics Moment Component From Cross ProductStatics Unnormalized Projection IS Not Direction Cosine

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Mixed review

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STAT:010219Cable tensions 5/3, 20/3, 20/3 kN keep the ring in equilibrium

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Statics Spatial Particle Force BalanceStatics Cable Tension Sign Audit

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Particle and rigid-body equilibriumEngineering Statics · Mixed review

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STAT:010220Vertical ties carry 6 kN and 4 kN; the ball-and-socket reaction is (-4,3,2) kN

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Statics Spatial Rigid Body MomentsStatics Ball Socket Tie Reactions

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Particle and rigid-body equilibriumEngineering Statics · Mixed review

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STAT:010221The two-force link carries 10 kN; the pin reaction (8,2) kN meets the other two lines at (3,3/4)

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Statics Three Force ConcurrencyStatics Two Force Member Direction

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Particle and rigid-body equilibriumEngineering Statics · Mixed review

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STAT:010235Smooth normals n1=(3/5,4/5), n2=(-4/5,3/5) with P i and 70 downward give N1=56-3P/5, N2=42+4P/5; contact iff -105/2<=P<=280/3

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Statics Two Smooth Normal EquilibriumStatics Unilateral Reaction Sign Window

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Particle and rigid-body equilibriumEngineering Statics · Mixed review

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STAT:010236Pin A at x=0 and upward roller B at x=4 with 12 down at x=-1 and P down at x=6: By=(3P-6)/2, Ay=15-P/2; contact iff P>=2

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Statics Pin Roller Overhang Moment BalanceStatics Upward Roller Liftoff Threshold

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Particle and rigid-body equilibriumEngineering Statics · Mixed review

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STAT:010322One section through BC, BE, and DE reads the three cut forces; joints and zero-force are not the method

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Truss Global Support ReactionsMethod OF Sections Three Cut

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Trusses, frames, and machinesEngineering Statics · Mixed review

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STAT:010323The hinge at B transmits force, not a couple; B on AB is not the force on BC

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Internal Hinge DisassemblyThree Pin Frame Equilibrium

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Trusses, frames, and machinesEngineering Statics · Mixed review

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STAT:010324Stage arms 0.60/0.15 and 0.20/0.05 multiply to 16P; the pins are 5P up and 20P down

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Compound Lever Mechanical AdvantagePin Reaction Action Reaction Audit

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Trusses, frames, and machinesEngineering Statics · Mixed review

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STAT:010337Triangle A(0,0),B(4,0),C(0,3) with three vertical rollers has m+r=2j=6 but support-wrench rank 2 and a horizontal mechanism

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Statics Truss Count Necessary Not SufficientStatics Support Wrench Rank Mechanism

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Trusses, frames, and machinesEngineering Statics · Mixed review

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STAT:010338Symmetric cable span 8 sag 2 under w=3 kN/m has H=12, support tension 12sqrt2, midspan y=x^2/8, slope 1, midspan tension 12

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Statics Parabolic Cable Horizontal ThrustStatics Cable Support Slope Tension

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Trusses, frames, and machinesEngineering Statics · Mixed review

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STAT:010425The hole subtracts area; y-bar stays on the midline and x-bar is not the hole center

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Composite Area Signed First MomentCentroid Symmetry And Hole

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Distributed loads, centroids, and resultantsEngineering Statics · Mixed review

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STAT:010426Three orthogonal wires have r_G=(16/25,27/50,8/25); gravity about O is not a wrench pitch

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Composite Wire Mass CenterGravity Moment About Origin

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Distributed loads, centroids, and resultantsEngineering Statics · Mixed review

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STAT:010439Vertical gate width 2 height 3 with top at the free surface and gamma=10 has F=90, center of pressure at depth 2, moment about the top 180

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Statics Hydrostatic Resultant ON RectangleStatics Center OF Pressure Versus Centroid

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Distributed loads, centroids, and resultantsEngineering Statics · Mixed review

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STAT:010440T-section web 2x3 on y=0..3 and flange 6x1 on y=3..4 has areas 6 and 6, ybar=5/2, Ix=17, Iy=20, Ixy=0

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Statics Composite T Section CentroidStatics Parallel Axis Second Moments

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Distributed loads, centroids, and resultantsEngineering Statics · Mixed review

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STAT:010441Linear p=3x+6y on 0<=x<=2, 0<=y<=1 has R=(0,0,-12), M_O=(-7,14,0), vertical resultant through (7/6,7/12)

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Statics Linear Pressure Force ResultantStatics Distributed Moment Line OF Action

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Distributed loads, centroids, and resultantsEngineering Statics · Mixed review

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STAT:010527A pushed block tips before it exhausts static friction

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Tip Versus Slide ThresholdContact Resultant Eccentricity

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Dry friction and impending motionEngineering Statics · Mixed review

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STAT:010528A half-wrap capstan doubles tension at impending slip

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Capstan Differential EquilibriumBelt Friction Torque Capacity

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Dry friction and impending motionEngineering Statics · Mixed review

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STAT:010529A square-thread screw raises easily enough but still self-locks

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Power Screw Friction AngleSelf Locking And Efficiency

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Dry friction and impending motionEngineering Statics · Mixed review

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STAT:010542Horizontal P on a 3-4-5 rough incline with W=100 and mu_s=1/2 admits 200/11<=P<=200; f=+500/11 downslope-impending, f=-100 upslope-impending, and f=0 at 75

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Statics Horizontal Push Incline ResolutionStatics Signed Coulomb Rest Window

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Dry friction and impending motionEngineering Statics · Mixed review

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STAT:010543Drum torque 100 on radius 1/2 needs |F|=200 and N=500 at mu=0.4; lever moments at A=(0.4,0.2) give P=180 versus P=20 according to drum sense

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Statics Drum Pad Friction Normal PairStatics Lever Brake Directional Moment

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Dry friction and impending motionEngineering Statics · Mixed review

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STAT:010630Four supporting cable segments give an ideal four-to-one block tackle

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Cable Length Virtual DisplacementIdeal Block Tackle Advantage

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Potential energy and virtual workEngineering Statics · Mixed review

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STAT:010631A torsional spring turns a rigid-link instability into a pitchfork

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Potential Energy Critical LoadDegenerate Equilibrium Bifurcation

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Potential energy and virtual workEngineering Statics · Mixed review

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STAT:010644External gears r=1/5 and 1/2 convert input 50 through 0.2 dθ1+0.5 dθ2=0 into output 125, tooth force 250, and opposite rotations

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Statics External Gear Constraint RatioStatics Virtual Work Gear Torque

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Potential energy and virtual workEngineering Statics · Mixed review

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STAT:010645Rolling wheel of radius 1/2 with Q=600 left at the center needs P=300 at the top; contact has zero virtual displacement but friction 300 right, N=1000, mu_min=0.30

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Statics Rolling Virtual Displacement RatioStatics Silent Contact Friction Recovery

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Potential energy and virtual workEngineering Statics · Mixed review

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STAT:010646Smooth vertical circle with V=-R(4cosθ+3sinθ) is stationary at sinθ=3/5, cosθ=4/5 with V''=5R>0 and inward reaction 5; the antipode has V''=-5R and is unstable

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Statics Circle Conservative PotentialStatics Second Derivative Stability Reaction

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Potential energy and virtual workEngineering Statics · Mixed review

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902011A 1.2 kN force acts along the line from A(0, 0, 0) to B(3 m, 4 m, 12 m).

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902012Force F = (50i + 80j − 40k) N is applied at corner G of a rectangular box with corners at O(0,0,0), A(0.6 m,0,0), B…

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902013A 250 N force acts in the negative y-direction at point Q(0.8 m, 0, 0.5 m).

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902014Using Varignon’s theorem, determine the moment about point A of the 600 N force applied at B on the L-shaped member.

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902015Two parallel forces of equal magnitude 400 N but opposite sense form a couple in the x–y plane.

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902016Replace the force F = (120i − 90j) N acting at point (0.4 m, 0.2 m) by an equivalent force–couple system at the ori…

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902017A 3 kN vertical downward force acts at the free end of a horizontal cantilever of length 2.4 m.

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902018The force system on a rigid body consists of F1 = 200i N at (0, 0.5 m), F2 = −150j N at (0.8 m, 0), and a couple of…

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902019Three forces act on a particle: 500 N directed 30° above the positive x-axis, 350 N directed 120° from the positive…

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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STAT:9902020A particle is in equilibrium under four concurrent coplanar forces.

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Force SystemsStatics Problem Solving

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Vectors, moments, couples, and equivalent force systemsEngineering Statics · Calculation

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Problem results

STAT:9902001A force of magnitude 480 N acts through the origin in the direction of the vector 3i − 6j + 2k.

STAT:9902002Resolve the 2.5 kN force acting at point A into Cartesian components if the line of action of the force makes angle…

STAT:9902003Point B lies at (4 m, −2 m, 3 m) and point C lies at (−1 m, 5 m, 1 m).

STAT:9902004Three concurrent forces act at point O: F1 = (200i − 150j) N, F2 = (−80i + 320j) N, and F3 = (50i − 90j) N.

STAT:9902005Forces of 120 lb, 200 lb, and 160 lb act along the sides of an equilateral triangle ABC of side length 3 ft, with s…

STAT:9902006A 650 N force is directed from point D(2 m, 0, 0) toward point E(0, 3 m, 6 m).

STAT:9902007Two forces act on a bolt: F_A = 80i − 60j (lb) and F_B has magnitude 100 lb and direction 40° above the negative x-…

STAT:9902008Express the force F = (−240i + 180j − 100k) N as a product of its magnitude and a unit vector in its direction.

STAT:9902009Four coplanar forces act at a joint: 300 N at 0°, 450 N at 70°, 200 N at 150°, and 350 N at 255°, where angles are…

STAT:9902010A force F = (80i − 40j + 60k) lb acts at point P(2 ft, 1 ft, −3 ft).

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Problem results

STAT:9902001A force of magnitude 480 N acts through the origin in the direction of the vector 3i − 6j + 2k.

STAT:9902002Resolve the 2.5 kN force acting at point A into Cartesian components if the line of action of the force makes angle…

STAT:9902003Point B lies at (4 m, −2 m, 3 m) and point C lies at (−1 m, 5 m, 1 m).

STAT:9902004Three concurrent forces act at point O: F1 = (200i − 150j) N, F2 = (−80i + 320j) N, and F3 = (50i − 90j) N.

STAT:9902005Forces of 120 lb, 200 lb, and 160 lb act along the sides of an equilateral triangle ABC of side length 3 ft, with s…

STAT:9902006A 650 N force is directed from point D(2 m, 0, 0) toward point E(0, 3 m, 6 m).

STAT:9902007Two forces act on a bolt: F_A = 80i − 60j (lb) and F_B has magnitude 100 lb and direction 40° above the negative x-…

STAT:9902008Express the force F = (−240i + 180j − 100k) N as a product of its magnitude and a unit vector in its direction.

STAT:9902009Four coplanar forces act at a joint: 300 N at 0°, 450 N at 70°, 200 N at 150°, and 350 N at 255°, where angles are…

STAT:9902010A force F = (80i − 40j + 60k) lb acts at point P(2 ft, 1 ft, −3 ft).