A shunt clipper uses v_i at node A, R=3.30 kΩ from A to node B, and a pn diode with…

A shunt clipper uses \(v_i\) at node \(A\), \(R=3.30\,\mathrm{k}\Omega\) from \(A\) to node \(B\), and a pn diode with anode at \(B\) and cathode at ground. The output is \(v_o=v_B\). No additional load is present. The forward drop at a fixed current \(I_{\mathrm{ref}}=1.00\,\mathrm{mA}\) is \[ V_F(T)=0.700\,\mathrm{V}+\gamma_F(T-25.0^\circ\mathrm{C}),\qquad \gamma_F=-2.00\,\mathrm{mV/K}. \] When the diode is on, use the constant-drop model at that \(V_F(T)\) (do not include \(r_s\)). When the diode is off it is an open circuit. Reverse leakage is neglected. At \(T=25.0^\circ\mathrm{C}\), determine the breakpoint \(v_i\) at which the diode turns on and the clipped value of \(v_o\) for \(v_i\) above the breakpoint. Repeat at \(T=85.0^\circ\mathrm{C}\). For a DC input \(v_i=5.00\,\mathrm{V}\), compute \(i_D\) at both temperatures and check that using \(V_F\) taken at \(I_{\mathrm{ref}}\) is consistent to within \(20\%\) with the actual on-current (i.e., report the relative discrepancy \(|i_D-I_{\mathrm{ref}}|/I_{\mathrm{ref}}\) at each temperature). Compute the temperature-induced change in the clipped output, \(\Delta v_o=v_o(85^\circ\mathrm{C})-v_o(25^\circ\mathrm{C})\).

A grounded shunt diode clips at whatever \(V_F(T)\) the constant-drop model assigns; temperature enters only through that drop.