Computer Architecture · Datapath and control implementation
A J-type jump instruction has the 32-bit encoding `0x0810000F`
Problem
A J-type jump instruction has the 32-bit encoding `0x0810000F`. Fields are opcode[31:26] \(=000010\) and addr[25:0] \(=\) the remaining bits. The jump target is formed as \(\{\,(\mathrm{PC}+4)[31:28],\,\mathrm{addr}[25:0],\,2'b00\,\}\). The instruction is fetched from address `0x00400000`. Compute \(\mathrm{PC}+4\), extract addr[25:0], and compute the 32-bit jump target in hexadecimal. Then prove that this concatenation always produces a word-aligned address.
Hint
The 26-bit jump field is *not* a complete 32-bit address; it is the middle field of a concatenation.
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